I have not understood how to do this challange

Question

Can any one help

even.py

import random
start = 5 
def even_odd(num):
    while True:
        num=random.radint(1, 99)
        if random.randint(1, 100) % 2 :
            print("{} is even".format(random.randint(1, 100)))
        else:
            print("{} is odd".format(random.randint(1, 100)))
        while True:
            star- =1
        return not num % 2

def even_odd(num)

Answer 1 · 2016-11-20T05:39:44Z

November 20, 2016 5:39am

Hi Suleiman,

The even_odd function is already complete as is. You don't need to add anything to it.

The challenge is asking you to create a while loop outside of the function. In this loop you will call even_odd(num) in order to test whether "num" is even or odd. The way even_odd works is that it will output "True" if the number is even and "False" if the number is odd.

Keep in mind that the random.randint() function will most likely generate a different number every time you call it, so using it in your string formatting probably won't be the same as the number you are testing. You only need to generate a random number once in this challenge.

I'd suggest reading the challenge again and go through it line by line. It walks you through the major steps required to solve it. And don't forget about using that "start" variable you created in order to control the while loop.

import random
start = 5

def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2

#while loop

Good luck.

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Suleiman Abdurozikov

Suleiman Abdurozikov

I have not understood how to do this challange

1 Answer

Ryan S

Ryan S