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Bas van Krieken
1,805 Pointsi just can't figure it out what am i doing wrong it says it only runs once
how do i fix it
var k = parseInt(0);
for (var i = 4; i<= 156; i += 1 ) {
k += i;
}
console.log(k);
3 Answers
Grace Kelly
33,990 PointsYou have the right idea, just a couple of minor things:
- This code challenge requires for you to log the number inside the for loop. You have done so outside the loop
- You don't need to increment your number inside the for loop as this is done already inside the parenthesis when you declare the loop
So looking at your code, we can make these small changes and ammend it like so:
for (var i = 4; i<= 156; i += 1 ) { //i += 1 increments i by one on each iteration of the loop
console.log(i) //log the number on each iteration of the loop
}
Making these small changes will make the code work :)
Hope that helps!!
Sam Baines
4,315 PointsHi Bas - its quite a simple mistake you have here - you need to make sure the console.log command is run within the loop not outside of it like you have it. Otherwise the loop runs for (i) through 157 times and then writes the value of (i) to the console. Code below:
for (var i = 4; i<= 156; i ++ ) {
console.log(i);
}
Hope this helps.
Bas van Krieken
1,805 Pointsthe adjustments do make it work but i still says it writes to many numbers