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Python Python Basics (2015) Letter Game App Even or Odd Loop

Posted by Jamel Stringer
Jamel Stringer
Courses Plus Student 906 Points

I need help

Challenge Task 3 of 3

Alright, last step but it's a big one. Make a while loop that runs until start is falsey. Inside the loop, use random.randint(1, 99) to get a random number between 1 and 99. If that random number is even (use even_odd to find out), print "{} is even", putting the random number in the hole. Otherwise, print "{} is odd", again using the random number. Finally, decrement start by 1.

Please I need to understand what I am doing wrong. This is my last exercise before I can move on.

even.py 
import random
start = 5
while start == 5:
    def even_odd(num):
        num = random.randint(1, 99)
        if randNum % 2 == 0:                             
            print("{} is even".format(num)
        else:
            print("{} is odd".format(num)
        start -1



    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
return not num % 2

2 Answers

Ryan S
Ryan S
27,276 Points
Ryan S
Ryan S
27,276 Points

Hi Jamel,

You aren't supposed to modify the even_odd() function. It was already written for you to be called upon in your while loop. The function will return true if a number is even, and false if it is odd. All your code should be outside of the function.

Good luck.

Jamel Stringer
PLUS
Jamel Stringer
Courses Plus Student 906 Points
Jamel Stringer
Jamel Stringer
Courses Plus Student 906 Points

Thank you Ryan that makes sense, but now I'm getting "wrong number of prints" error.....SMH!

import random start = 5 while start is True: num = random.randint(1, 99) if num % 2 ==0: print("{} is even".format(num)) else: print("{} is odd".format(num)) start -= 1

def even_odd(num): # If % 2 is 0, the number is even. # Since 0 is falsey, we have to invert it with not. return not num % 2

Ryan S
Ryan S
27,276 Points
Ryan S
Ryan S
27,276 Points

You have the right idea with the logic and it is possible to pass the challenge by going that route, however the challenge prefers that you actually use the even_odd()` function to determine whether the random integer is even or odd. So your code should be written below the function in order to make use of it.

eg:

if even_odd(num) == True:
   # code here

Also, take another look at your while condition. The "is" keyword is not meant for this type of comparison. You should make sure to use the standard comparison operators, like "==" and "!=". Also, remember that the loop will run until start is False, and the integer 0 is evaluated as False.

Hope this helps.