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Python Python Collections (2016, retired 2019) Lists Disemvowel

a a
a a
1,101 Points
Posted by a a
a a
1,101 Points

I need help in code challenge

Python 3.6.3 |Anaconda, Inc.| (default, Oct 15 2017, 03:27:45) [MSC v.1900 64 bit (AMD64)] on win32
Type "help", "copyright", "credits" or "license" for more information.
>>> def disemvowel(word):
...   word_1 = list(word)
...   for words in word_1:
...     if "a" in words:
...       words.remove("a")
...     if "A" in words:
...       words.remove("A")
...     if "i" in words:
...       words.remove("i")
...     if "I" in words:
...       words.remove("I")
...     if "u" in words:
...       words.remove("u")
...     if "U" in words:
...       words.remove("U")
...     if "e" in words:
...       words.remove("e")
...     if "E" in words:
...       words.remove("E")
...     if "o" in words:
...       words.remove("o")
...     if "O" in words:
...       words.remove("O")
...     word_2 = ",".join(words)
...     print(word_2)
...
>>> disemvowel("HUBxcbeYq")
H
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "<stdin>", line 15, in disemvowel
AttributeError: 'str' object has no attribute 'remove'
>>>
disemvowel.py 
def disemvowel(word):
  word_1 = list(word)
  for words in word_1:
    if "a" in words:
      words.remove("a")
    if "A" in words:
      words.remove("A")
    if "i" in words:
      words.remove("i")
    if "I" in words:
      words.remove("I")
    if "u" in words:
      words.remove("u")
    if "U" in words:
      words.remove("U")
    if "e" in words:
      words.remove("e")
    if "E" in words:
      words.remove("E")
    if "o" in words:
      words.remove("o")      
    if "O" in words:
      words.remove("O")
    word_2 = ",".join(words)
    print(word_2)

1 Answer

Steven Parker
Steven Parker
231,236 Points
Steven Parker
Steven Parker
231,236 Points

The loop iterates through the list "word_1" and separates each letter into a string named "words". But strings do not have a "remove" method. Did you intend to perform that method on the list ("word_1") instead?

A few other hints:

  • altering a list while iterating on it can cause items to be skipped
  • you can't "join" a string, did you mean to do that on the list?
  • joining with a "," will not rebuild the word, but will create a string of comma-separated letters