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Start your free trialChastin Davis
Courses Plus Student 2,299 PointsI need to return a list and a Dict together??
I have the dict and string list i believe. How do I return them using *. Maybe I'm confused about the *.
# Example:
# values = [{"name": "Michelangelo", "food": "PIZZA"}, {"name": "Garfield", "food": "lasagna"}]
# string_factory(values)
# ["Hi, I'm Michelangelo and I love to eat PIZZA!", "Hi, I'm Garfield and I love to eat lasagna!"]
template = "Hi, I'm {name} and I love to eat {food}!"
def string_factory(values):
string_list = []
new_list = []
for value in values:
string_list.append(value["name"])
new_list.append([template.format(name= value["name"] , food= value["food"])])
together = string_list + new_list
return together
1 Answer
Steven Parker
231,275 PointsLet's ignore the "**" for a moment, you still have some other issues:
- you don't need a separate list for the name, it's part of the template
- you don't need to wrap the result of the format in braces to use append on it
- the return should happen after the loop, not inside it
Now if you fix the issues, you can pass the challenge, but the whole point was to "test unpacking dictionaries" by "using **
for each dictionary". Doing this will greatly simplify the call to format since you only need to pass it "**value
" and that will unpack the keyword arguments for you.