I realize that its printing the whole range to the console each time through the loop instead of each number, but why?

Question

But why???
```script.js
var num = ' ';
for ( var i = 4; i <= 156; i += 1 ) {
  num +=  i + ' ' ;
  console.log(num);
}
```

Brian Holland · Accepted Answer

It's not actually not printing the whole range every time.  It prints increasingly:

4
4 5
4 5 6
...
4 5 6 7 8..... 156

First of all, you don't actually need a 'num' variable at all.  Just log each number once with console.log(i).
Second, javascript kind of 'bends' the typing of some variables when it can.  Spot the difference:

str = ' '
num = []
obj = {}

Javascript assumes that you know that since num was declared as a string (i.e., with ' 's surrounding it), you mean you want to concatenate i to num as a string when you say num += i + ' '.
It's like the opposite of if I were to say console.log("i").
W3 Schools has a good page (http://www.w3schools.com/js/js_datatypes.asp) about it.

Christian Weatherford · Answer

The following code will print each number once, but each on its own line. No need for a "num" variable, just log out the value of "i".
javascript
for ( var i = 4; i <= 156; i += 1 ) {
  console.log(i);
}

However, if you want it all on one line, I'd recommend using your approach but only logging to the console after/outside the for loop. So it would be called once, after you're done building the string.
```javascript
var num = ' ';
for ( var i = 4; i <= 156; i += 1 ) {
  num +=  i + ' ' ;
}
console.log(num);
```

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Jake Schmidt

Jake Schmidt

I realize that its printing the whole range to the console each time through the loop instead of each number, but why?

2 Answers

Brian Holland

Brian Holland

Christian Weatherford

Christian Weatherford