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Oszkár Fehér
Treehouse Project Revieweri remade my code and this one it's not excepted too. why?
i am confused, i made to different codes and non of them is excepted, it's me who see the quiestion differntly or i am not for this....
# combo([1, 2, 3], 'abc')
# Output:
# [(1, 'a'), (2, 'b'), (3, 'c')]
def combo(*args):
az_en_listam = []
count = 0
for a, b in args:
for x in b:
az_en_listam.append((a[count], x))
count +=1
return az_en_listam
1 Answer
Christopher Shaw
Python Web Development Techdegree Graduate 58,248 PointsTo put you on track, the question says Create a function named combo that takes two ordered iterables. As it tells you the number of arguments, do not use *args (this is for when you do not know the number of arguments).
Start with something like:
def combo(number_list, character_string):
az_en_listam = []
count = 0
for number in number_list:
Oszkár Fehér
Treehouse Project ReviewerOszkár Fehér
Treehouse Project Revieweri do my best to create on my on the codes and i relly like what i do here but i see that i doing it wrong all the time....