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JavaScript JavaScript Loops, Arrays and Objects Simplify Repetitive Tasks with Loops Refactor Using a Loop

Posted by Emis Zakitis
Emis Zakitis
139 Points

I think I did it right, but.....

I have to make a look to console.log 2 to 24 I did it? Heelp It sais I loogen in 23 but had to log in 12? i dont understand

script.js 
for (  i = 2; i<24; i++) {
console.log(2);
}
index.html 
<!DOCTYPE html>
<html>
<head>
  <meta charset="utf-8">
  <title>JavaScript Loops</title>
</head>
<body>
<script src="script.js"></script>
</body>
</html>

3 Answers

jared eiseman
jared eiseman
29,023 Points
jared eiseman
jared eiseman
29,023 Points

There's a couple of things here.

For starters, in the loop, (i = 2; i<24; i++), the last condition is shorthand for i = i + 1. You need your loop to count by even numbers, so a simple implementation of this would be to do i = i + 2, or i += 2 for short. (also, this will only count up to 24, not including 24)

Secondly, you're logging 2 each time. So with the correct loop you would log 2 out a bunch of times. Consider logging the variable instead.

Here is a working code sample:

for (var i = 2; i <= 24; i += 2) {
    console.log(i);
}
Austin Erb
Austin Erb
6,827 Points
Austin Erb
Austin Erb
6,827 Points

You are close.

You start off with i = 2 which is good, but you are missing the 'var' keyword before i.

Also, your loop stops when i < 24 which is close, but because you use < instead of <=, your program will stop before it gets to 24.

And finally, you need to increment your i variable by += 2 instead of += 1.

I hope this explanation was understandable.

Emis Zakitis
Emis Zakitis
139 Points
Emis Zakitis
Emis Zakitis
139 Points

thanks, I dont know witch I would rate ghestr i'l take the first one...