Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

iOS Swift Basics Swift Operators Working With Operators

Posted by Joshua Nilsson
Joshua Nilsson
846 Points

I think I did the second part right but I can't do the first.

I don't know what it means by WITHOUT COMPUTING.

Heres the full question: In this task, we have two math operations. Without computing the values of those operations, we'd like to know if the first operation, someOperation is greater than, equal to or less than anotherOperation.

Use the greater than or equal to operator (written as >=) and assign the Boolean result of the comparison to a constant named isGreater

operators.swift 
// Enter your code below
let value = 200
let divisor = 5

let someOperation = 20 + 400 % 10 / 2 - 15
let anotherOperation = 52 * 27 % 200 / 2 + 5

// Task 1 - Enter your code below
let result = value % divisor

// Task 2 - Enter your code below
let isPerfectMultiple = 0 == result

someOperation == anotherOperation
someOperation > anotherOperation
someOperation < anotherOperation

let isGreater: Bool = anotherOperation >= someOperation

1 Answer

Steven Parker
Steven Parker
231,236 Points
Steven Parker
Steven Parker
231,236 Points

I think you're misinterpreting the instructions. For task 2, there's not two separate parts. The first paragraph is just explanation of the objective.

"Without computing" just means that you should use the variables by name and not try to determine what the numeric value of the expressions resolves to yourself.