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Python Python Collections (2016, retired 2019) Dictionaries Word Count

Posted by MOUSLIM BOUABDALLAH
MOUSLIM BOUABDALLAH
Courses Plus Student 17,430 Points

I think i find the solution but the Try again! still there!!

def word_count(phrase): phrase = phrase.lower() b = {} for word in phrase.split(): if word in b: b[word] += 1 else: b[word] = 1 print(b)

word_count("I do not like it Sam I Am")

wordcount.py 
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(phrase):
    phrase = phrase.lower()
    d = {}
    for word in phrase.split():
        if word in d:
            d[word] += 1
        else:
            d[word] = 1
    print(d)

word_count("I do not like it Sam I Am")

2 Answers

Jennifer Nordell
seal-mask
STAFF
.a{fill-rule:evenodd;}techdegree
Jennifer Nordell
Treehouse Teacher
Jennifer Nordell
.a{fill-rule:evenodd;}techdegree
Jennifer Nordell
Treehouse Teacher

Hi there! You're 99% of the way there and doing terrific! My guess is here that you are printing your results to test them, which is great outside of the challenge. However, the challenge asks you to return the results... not print them. Also, note that you will not need to call the function yourself. Treehouse will be doing that for you.

I feel like you can get it with this teensy hint, but let me know if you're still stuck! :sparkles:

MOUSLIM BOUABDALLAH
MOUSLIM BOUABDALLAH
Courses Plus Student 17,430 Points

Yeap, i forgot to return the result, thank you ^_^

nakalkucing
nakalkucing
12,964 Points
nakalkucing
nakalkucing
12,964 Points

Hey Mouslim! You've got your code right until you get to the place where you're supposed to return it. You have it set to print. :) Was that clear? Let me know if you need more help. :)

Best,

Nakal

MOUSLIM BOUABDALLAH
MOUSLIM BOUABDALLAH
Courses Plus Student 17,430 Points

I think it's clear thank's a lot.