Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trial
Brendan Whiting
Front End Web Development Techdegree Graduate 84,738 PointsI think my answer could be better
Challenge accepted my code but I have a feeling it's less that ideal. Is there a better way to iterate through my list?
def string_factory(list, string):
string_list = []
for idx in range(len(list)):
string_list.append(string.format(**list[idx]))
return string_list
dicts = [
{'name': 'Michelangelo',
'food': 'PIZZA'},
{'name': 'Garfield',
'food': 'lasanga'},
{'name': 'Walter',
'food': 'pancakes'},
{'name': 'Galactus',
'food': 'worlds'}
]
string = "Hi, I'm {name} and I love to eat {food}!"
2 Answers
William Li
Courses Plus Student 26,868 PointsHi there,
Your solution is okay, but you could simplify it a bit by not using the range() function. Like such
def string_factory(ls, string):
string_list = []
for i in ls:
string_list.append(string.format(**i))
return string_list
I believe that makes the code cleaner and easier to read. Cheers.
Andreas cormack
Python Web Development Techdegree Graduate 33,011 PointsHi
another way of doing it.
def string_factory(myList,myString):
new_list = []
for dict in myList:
new_list.append(myString.format(**dict))
return new_list
Brendan Whiting
Front End Web Development Techdegree Graduate 84,738 PointsBrendan Whiting
Front End Web Development Techdegree Graduate 84,738 PointsThanks!