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Python Python Collections (2016, retired 2019) Dictionaries Word Count

igor corrales
igor corrales
2,474 Points
Posted by igor corrales
igor corrales
2,474 Points

I think my code is oK but .....

I check in my console my code and it is working but they don't let me pass....some help please

wordcount.py 
# E.g. word_count("I do not like it Sam I AI do not like it Sam I Am"m") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(cadena):
    cadena_min = cadena.lower()
    lista = cadena_min.split()
    dict = {}
    for palabra in lista:
        if palabra in dict:
            dict[palabra] += 1
        else:
            dict[palabra] = 1
    print(dict)

1 Answer

Alex Koumparos
seal-mask
.a{fill-rule:evenodd;}techdegree
Alex Koumparos
Python Development Techdegree Student 36,887 Points
Alex Koumparos
.a{fill-rule:evenodd;}techdegree
Alex Koumparos
Python Development Techdegree Student 36,887 Points

Hi Igor,

The challenge instructions tell you:

The function needs to return a dictionary.

Your function doesn't return anything, it just prints the dictionary to the console.

Cheers

Alex