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shirshah sahel
10,035 PointsI try to log in XMLHttpRequest in console but it gives me error.
<html>
<head>
<meta charset="utf-8">
<link href='//fonts.googleapis.com/css?family=Varela+Round' rel='stylesheet' type='text/css'>
<link rel="stylesheet" href="css/main.css">
<title>AJAX with JavaScript</title>
<script>
var xhr= new XMLHttpRequest();
xhr.onreadystatechange = function(){
if(xhr.readyState === 4){
document.getElementById('ajax').innerHTML= xhr.responseText;
}
};
xhr.open('GET', 'sidebar.html');
xrh.send();
</script>
</head>
<body>
<div class="grid-container centered">
<div class="grid-100">
<div class="contained">
<div class="grid-100">
<div class="heading">
<h1>Bring on the AJAX</h1>
</div>
<div id="ajax">
</div>
</div>
</div>
</div>
</div>
</body>
</html>
3 Answers
Anders Blom
9,124 PointsHi shirshah, at the end of your script-tag, you seem to have a small typo. It should be ´xhr.send()rather than ´xrh.send().
That small correction should make your AJAX request send properly, and fill up the #ajax-div.
shirshah sahel
10,035 PointsThanks Mitten, it was a miss spilling issue.
shirshah sahel
10,035 PointsThanks Mr Blom, That is exactly what it was. after the correction of mis spilling it worked.
Jonathan Mitten
Courses Plus Student 11,197 PointsJonathan Mitten
Courses Plus Student 11,197 PointsHi shirshah, I don't see any console.log() in your code nor in the attached workspace. Where are you trying to log the response object? Please provide the code exactly as it is when it fails. Thanks!