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Marina Klimi
Courses Plus Student 1,080 PointsI will need feedback and help on my code.
I am trying to write the code for this question but I do not think so I do it right. Please have a look and let me know. "function returnValue ( echo ) { return echo ; alert ( returnValue ); } alert ( returnValue ); var echo = returnValue(alert); " Thanks in advance. Marina
function returnValue ( echo ) {
return echo ;
alert ( returnValue );
}
alert ( returnValue );
var echo = returnValue(alert);
<!DOCTYPE HTML>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>JavaScript Basics</title>
</head>
<body>
<script src="script.js"></script>
</body>
</html>
2 Answers
Daniel Boisselle
Front End Web Development Techdegree Student 17,438 PointsThe remaining code inside a function will not run after a value has been returned, the execution context will close. Therefore calling 'alert' on line 3 will not run.
On your line 6 you need to be passing in a string, but you're passing in the 'alert' function which doesn't make much sense in this case.
Hope this helps!
function returnValue (argument) {
return argument
}
var echo = returnValue("Passing in a string argument")
Marina Klimi
Courses Plus Student 1,080 PointsThank you very much have a good night. Greetings Marina