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Python Python Collections (2016, retired 2019) Dictionaries Word Count

Caleb Shook
Caleb Shook
3,194 Points
Posted by Caleb Shook
Caleb Shook
3,194 Points

I wrote this in Workspaces and it worked perfectly...

In Workspaces, this worked fine but after copy and pasting it into the challenge and fixing the indentation errors it doesn't pass. I get an error saying that I didn't lowercase the string, but I did and tested that as well.

wordcount.py 
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.

def word_count(string):
    words = {}
    word = ""
    end = len(string)
    pos = 0
    for letters in string.lower():
        pos+= 1
        if letters!= ' ' and pos != end:
            word += letters.lower()
        elif pos == end:
            word+= letters.lower()
        if word in words:
            words[word] += 1
            word = "" 
            continue
        elif word in words:
            words[word] += 1
            word = ""
            continue
        else:
            words.update({word:1})
            word = ""
            continue
    return words

2 Answers

james south
seal-mask
.a{fill-rule:evenodd;}techdegree seal-36
james south
Front End Web Development Techdegree Graduate 33,271 Points
james south
.a{fill-rule:evenodd;}techdegree seal-36
james south
Front End Web Development Techdegree Graduate 33,271 Points

this code returns a dict of the counts of every letter in the string, not every word. look at the split method to break the string of words into a list of words, and count those up and return a dict of that.

Caleb Shook
Caleb Shook
3,194 Points
Caleb Shook
Caleb Shook
3,194 Points

I am not sure I understand. When I run it, I get back a dict of words with how many times they have occurred.

Caleb Shook
Caleb Shook
3,194 Points
Caleb Shook
Caleb Shook
3,194 Points

I redid the code but it is still failing. 

def word_count(string):
    words = string.lower().split(' ')
    wordCount = dict()
    for word in words:
        if word in wordCount:
            wordCount[word] += 1
        else:
            wordCount.update({word:1})
    return wordCount ```