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Start your free trialJason Pallone
895 PointsIf argument can be turned into a int challenge, need help please
This is what i got so far, the error it is giving is just bummer try again, so im a little lost here?
# EXAMPLES
# squared(5) would return 25
# squared("2") would return 4
# squared("tim") would return "timtimtim"
def squared(string):
try:
if int(string):
return squared(string)
except ValueError:
return(string * len(string))