I'm at a loss. I thought I set up a condition that would skip printing an index item and index "0" if it were an "a"?

Question

I don't know what to do from here.

breaks.py

def loopy(items):
    for item in items:
        if items[0] == "a":
            continue
        else:
            print(item)

Answer 1 · 2017-01-11T01:51:19Z

January 11, 2017 1:51am

Your code is correct, you just have a typo in it. You use the word "items" in your if statement rather than "item" which is the thing you are actually supposed to be checking the index of.

If you change "items" to "item" like this:

def loopy(items):
    for item in items:
        if item[0] == "a":
            continue
        else:
            print(item)

Then your code will pass.

Answer 2 · 2017-01-11T02:13:57Z

January 11, 2017 2:13am

# I tried the same thing as you
# item in this case is "abc" so it must me item[0]
# not items[0]
# items would be the whole list
def loopy(items):
    # Code goes here
    for item in items:
        if item[0] == "a": # <--- here
            continue
        else:
            print(item)

Answer 3 · 2017-01-11T02:59:41Z

January 11, 2017 2:59am

Thanks so much. Much appreciated. I'm on may way

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Jeff Ness

Jeff Ness

I'm at a loss. I thought I set up a condition that would skip printing an index item and index "0" if it were an "a"?

3 Answers

andren

andren

john larson

john larson

andren

andren

john larson

john larson

Jeff Ness

Jeff Ness