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Python Python Collections (2016, retired 2019) Dictionaries String Formatting with Dictionaries

Heidi Ulrich
Heidi Ulrich
4,624 Points
Posted by Heidi Ulrich
Heidi Ulrich
4,624 Points

I'm doing as asked, what goes wrong?

I've read the instructions over and over, and copied the samples to match my function. Now I get several errors, no matter what I change. How do I do this?

string_factory.py 
# Example:
# values = [{"name": "Michelangelo", "food": "PIZZA"}, {"name": "Garfield", "food": "lasagna"}]
# string_factory(values)
# ["Hi, I'm Michelangelo and I love to eat PIZZA!", "Hi, I'm Garfield and I love to eat lasagna!"]

values = [{"name": "Michelangelo", "food": "PIZZA"}, {"name": "Garfield", "food": "lasagna"}]
template = "Hi, I'm {name} and I love to eat {food}!"
new = []

def string_factory(**argument):

    for key in argument:
        thestring = template.format(name=key, food=argument.get(key))
        new.append(thestring)
    return new

string_factory(values)
andetin
andetin
5,263 Points

Hello,

Your function should take a list as an argument, and you should format your template with **kwargs. So:

values = [{"name": "Michelangelo", "food": "PIZZA"}, {"name": "Garfield", "food": "lasagna"}]
template = "Hi, I'm {name} and I love to eat {food}!"
new = []

def string_factory(argument):
    for key in argument:
        thestring = template.format(**key)
        new.append(thestring)
    return new

string_factory(values)

2 Answers

Ari Misha
Ari Misha
19,323 Points
Ari Misha
Ari Misha
19,323 Points

Hiya Heidi! This might help ya a bit:

def string_factory(argument):
    thestring = []
    for key in argument:
        thestring.append(template.format(name=key['name'], food=key['food']))
    return thestring

If you want me to break it down more, lemme know. (:

Heidi Ulrich
Heidi Ulrich
4,624 Points
Heidi Ulrich
Heidi Ulrich
4,624 Points

andetins answer worked! I understand it better now. Thanks!