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Python Python Collections (2016, retired 2019) Dictionaries Word Count

Posted by Joshua Jones
Joshua Jones
4,756 Points

I'm not sure why this code is not marked as correct

I wrote this code, based on the previous videos. It marks as incorrect, yet I tested the code in workspaces with multiple strings and it gave the correct output there. I'm not sure why this code doesn't work, is there anyone who can help?

wordcount.py 
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.

def word_count(text):
    text = text.lower()
    text = text.split(" ")
    test_dict = {}
    for word in text:
#        if word == "": # For an input with a double space, e.g. word_count("   ")
#            continue
        if word in test_dict:
            test_dict[word] += 1
        else:
            test_dict[word]=1
    return test_dict
Steve Hunter
Steve Hunter
57,712 Points

Very odd - the output of that looks fine. I'll see what I can figure out.

1 Answer

Steve Hunter
Steve Hunter
57,712 Points

Fixed - use the default split, so call it with no parameter. 

# not this
    text = text.split(" ")
# but this
    text = text.split()

That handles multiple whitespace entries better.

Steve.

Joshua Jones
Joshua Jones
4,756 Points

Thank you very much!