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Python Python Collections (2016, retired 2019) Lists Disemvowel

Jesse Ferguson
Jesse Ferguson
1,419 Points
Posted by Jesse Ferguson
Jesse Ferguson
1,419 Points

I'm stuck

I don't know how to do this

disemvowel.py 
def disemvowel(word):
    try:
        word.remove('a')
        word.remove('A')
        word.remove('E')
        word.remove('e')
        word.remove('I')
        word.remove('i')
        word.remove('O')
        word.remove('o')
        word.remove('U')
        word.remove('u')
    except ValueError:
        pass
    return word

1 Answer

Chris Freeman
MOD
Chris Freeman
Treehouse Moderator 68,441 Points
Chris Freeman
Chris Freeman
Treehouse Moderator 68,441 Points

Your approach doesn't handle these cases:

  • if the word is a string, strings do not have a remove method
  • any vowel appearing more than once will not be removed
  • if any vowel is not found the try block to exit then return the current state of word

Suggestion: convert the word to a list then use a for loop to extract the non-vowels rejoin the non-vowels back into a string and return it.

Post back if you need more help. Good luck!!!