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Python Python Collections (2016, retired 2019) Dictionaries Word Count

Moses Ong
Moses Ong
165 Points
Posted by Moses Ong
Moses Ong
165 Points

I'm stuck on this question tho

Lost at how I should assign the key values based on the number of same occurring word within the argument

wordcount.py 
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.

def word_count(**string):
    for word in word_counts: 
        if word == 
    return **string.lower()

1 Answer

Steven Parker
Steven Parker
230,995 Points
Steven Parker
Steven Parker
230,995 Points

If the word isn't in the dictionary, add it with a count of 1. And if the word is in the dictionary already, raise the count by 1 more.