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Start your free trialFurkan Demirtürk
7,940 Pointsin if conditions teacher wrote parseInt(guess) === randomNumber but we used == to check integers? Am ı wrong?
in if conditions teacher wrote parseInt(guess) === randomNumber but we used == to check integers? Am ı wrong?
1 Answer
Steven Parker
231,248 PointsThese both check for equal value, but the triple one ("===") also checks for the same type.
So. for examples:
if (42 == "42") console.log("Numbers match strings with ==");
if (42 === "42") console.log("This message will not appear");
Dan Otieno
23,495 PointsDan Otieno
23,495 Points== does a type conversion and the === does not.
parseInt("0") === 0 true, parseInt("2") === 2 true, "2" === 2 false, 2 === 2 true, "2" == 2 true