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Python Python Basics (2015) Number Game App Squared

Sergio Saavedra
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Sergio Saavedra
Python Web Development Techdegree Student 1,069 Points
Posted by Sergio Saavedra
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Sergio Saavedra
Python Web Development Techdegree Student 1,069 Points

In my workspaces this code seems to work fine. I don't know where is the failure. Can anyone help me? Thanks.

below you can see the code

squared.py 
def squared(var):
    try:
        if var == int(var):
            return var ** 2  
    except ValueError:
        return var * int(len(var))
Yasser Arenas
Yasser Arenas
5,879 Points
Yasser Arenas
Yasser Arenas
5,879 Points

You are comparing a string to an integer ('2' == 2). Try to cast the left side to an integer too. do not forget to cast it again when it enters to the if statement. :)

Sergio Saavedra
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.a{fill-rule:evenodd;}techdegree
Sergio Saavedra
Python Web Development Techdegree Student 1,069 Points
Sergio Saavedra
.a{fill-rule:evenodd;}techdegree
Sergio Saavedra
Python Web Development Techdegree Student 1,069 Points

I have solvented it replacing "if" statement as below: try: if var * 1 == var return var ** 2 except ValueError: return var * int(len(var))