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Jorge Gimeno
5,956 PointsIn the breaks.py challenge, none of the code snippets seem to work. The error message gives no reason why.
def loopy(items): for item in items: print item if item == 'STOP': break
Was the code I tried. The website only gives me back the "Bummer! Try again!" message with no details.
def loopy(items):
for item in items:
print item
if item == 'STOP':
break
1 Answer
Grigorij Schleifer
10,365 PointsHi Jorge,
try this code:
def loopy(items):
for x in items:
if x == 'STOP':
break
print(x)
The for loop goes first (you are completely right), but before printing the result the if condition should check whether x is STOP or something else. If x is equals to STOP then the loop will break x will not be printed. If x is not equals STOP the loop goes on and x will be printed.
It is possible that 'STOP' is on index 0 like this:
items = ['STOP', 'item_one', 'item_two']
So the loop will enter items see STOP and "break".
In my first answer I forgot to put parenthesis for the print method. Sorry for that :(
I hope this is a better answer
Grigorij
Jorge Gimeno
5,956 PointsJorge Gimeno
5,956 PointsThere was no error message, so all I can come up with is that the print statement raised an error without the parenthesis. Thanks for your help!
-Jorge