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Bryce Weaver
9,299 PointsInside the foreach loop, we should only display one <li> tag for each flavor. The one list item should display the value
I'm stuck.....
2 Answers
Carter Meyers
3,236 PointsIn case the "one <li >" tag bit was confusing, what the instructions really mean is one "pair" of <li> tags, which is to say an <li> and an </li>.
Before you start the foreach loop, what you'll want to do is start the unordered list, as all we're going to be doing with the foreach loop is building the items within a single, not the list itself. Using the same logic, we'll end the unordered list (</ul>) only after our foreach loop has finished.
Therefore, the code we'd use would look like this:
<ul> <!-- We start our unordered list. -->
<?php foreach ($flavors as $flavor) { ?> <!-- We start our foreach loop. -->
<li><?php echo $flavor; ?></li> <!-- We tell the server what we want to do with each item in our array. In this case, convert it to an HTML list item. -->
<?php } ?> <!-- We end our foreach loop.
</ul> <!-- We end our unordered list, as we've now finished displaying every item in our array.
Bryce Weaver
9,299 PointsThank you! Helped a bunch!
Paul Kirsch
2,894 PointsPaul Kirsch
2,894 Pointsyeah thanks from me too!