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PHP Build a Simple PHP Application Working With Functions Introducing User-Defined Functions

Posted by Stephanie Grove
Stephanie Grove
Courses Plus Student 2,144 Points

Introducing User-Defined Functions: mimic_array_sum() challenge #3 confusion.

In the main code, outside of the function, use the new mimic_array_sum() function you just wrote. Store the return value in a variable called $sum, and then display that sum to the screen.

Now I believe I could create the variable above the function which would outside or below it which would be outside, so between that and calling the function error message, I am getting more confused. Any help, first time asking question in here since starting the PHP development.

<?php

function mimic_array_sum($array) { $total = 0; foreach($array as $number){ $total = $total + $number; } return $total; } $sum = $total; $palindromic_primes = array(11, 757, 16361); call_user_func_array('mimic_array_sum', $sum);

?>

2 Answers

Stone Preston
Stone Preston
42,016 Points
Stone Preston
Stone Preston
42,016 Points

here are your issues:

$sum = $total;
 $palindromic_primes = array(11, 757, 16361);
 call_user_func_array('mimic_array_sum', $sum);

you are correct in that you can place your $sum variable outside the function by placing it below it, but you are assigning it the wrong value. $total is outside of the scope since its defined inside the function, it can only be accessed there, not outside it. you are supposed to assign $sum a value using your new mimic function and the palidromic_primes array thats defined for you and echo it like so (place it after your function definition):

$palindromic_primes = array(11, 757, 16361);
$sum = mimic_array_sum($palindromic_primes);
echo $sum;
Stephanie Grove
PLUS
Stephanie Grove
Courses Plus Student 2,144 Points
Stephanie Grove
Stephanie Grove
Courses Plus Student 2,144 Points

Thank you for your help, It worked.