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JavaScript JavaScript Basics (Retired) Creating Reusable Code with Functions Random Number Challenge, Part II Solution

Jeremi Watabiki
Jeremi Watabiki
4,833 Points
Posted by Jeremi Watabiki
Jeremi Watabiki
4,833 Points

Is the 'else' clause necessary to return the random number generated?

function getRandomNumber( lower, upper ) {
  if ( isNaN(lower) || isNaN(upper) ) {
    throw new Error ('You did not enter a valid number.');
  }
  else {
    return Math.floor(Math.random() * (upper - lower + 1)) + lower;
  }
}

console.log( getRandomNumber( 9, 24 ) );
console.log( getRandomNumber( 1, 100 ) );
console.log( getRandomNumber( 200, 500 ) );
console.log( getRandomNumber( 1000, 20000 ) );
console.log( getRandomNumber( 50, 'one' ) );

2 Answers

Matthew Vega
Matthew Vega
16,391 Points
Matthew Vega
Matthew Vega
16,391 Points

No, but it doesn't hurt anything. You could leave it in or take it out. The function will behave the same way as far as the caller is concerned.

If either isNaN condition is true, the error will be thrown and control will not return to this function. If neither input is NaN, the 'if' block is skipped and the random number will be returned.

Tyler Haas
Tyler Haas
20,623 Points
Tyler Haas
Tyler Haas
20,623 Points

the else can be omitted since the program would exit if the if statement returns true.