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Python Python Collections (2016, retired 2019) Dictionaries Word Count

Mattan Yedidya
Mattan Yedidya
1,084 Points
Posted by Mattan Yedidya
Mattan Yedidya
1,084 Points

Is the problem that I am trying to create a key off of a value that may not exist? Thanks!

Need help pls!

wordcount.py 
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.

def word_count(string):
    string_list = string.list()
    temp = {}
    for item in string_list:
        temp[item] = temp[item] + 1
Bapi Roy
Bapi Roy
14,237 Points
Bapi Roy
Bapi Roy
14,237 Points 
def word_count(str):
    temp_dict = {}
    str_list = str.lower().split(" ")

    for i in  str_list:
        if i  in temp_dict:
            temp_dict[i] = temp_dict[i] + 1
        else:
            temp_dict[i] =  1

    return temp_dict

try this

1 Answer

Krishna Pratap Chouhan
Krishna Pratap Chouhan
15,203 Points
Krishna Pratap Chouhan
Krishna Pratap Chouhan
15,203 Points

You have to use split function() over the string. Split(arg) function splits the string on the basis of 'arg' passed into it.

Remember... Don't pass any arguments in split().[by default, if not specified argument is space.]

# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.

def word_count(string):
    words = string.lower().split()
    res = {}
    for word in words:
        if word in res.keys():
            res[word] += 1
        else:
            res[word] = 1
    return res