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Hasan Jafri
2,859 PointsIs there a better way? (improving my solution)
I recently completed the Word count dictionary challenge but know my code is not written in the best possible way for this challenge:
this is how it looks:
def word_count(string):
lower_case = string.lower().split()
d={}
for letter in lower_case:
d[letter] = 0
for letter in lower_case:
d[letter] += 1
return d
I was wondering if I could get some ideas on a better way to resolve the challenge
1 Answer
ds1
7,627 PointsHi, Hasan Here's one way to solve it:
def word_count(astring):
results = {}
alist = astring.lower().split()
for item in alist:
mycount = alist.count(item)
results[item] = mycount #could also use "results.update({item: mycount})"
return results
Also, a helpful hint that I had to figure out the hard way, if you type ``` before and after the code you paste in, it shows up in a block (like above) and makes it easier for people to read. Hope this helps! D.