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Start your free trialDaniel Springer
Courses Plus Student 5,090 PointsIs there a better way to solve this challenge?
Given this challenge is there a shorter more efficient way to solve this?
grocery_item = { "item" => "Bread", "quantity" => 1, "brand" => "Treehouse Bread Company" }
has_bread = grocery_item.has_value?("Bread")
grocery_item.store("food", has_bread)
1 Answer
William Li
Courses Plus Student 26,868 PointsPersonally I'd solve the part 1 this way
grocery_item = { "item" => "Bread", "quantity" => 1, "brand" => "Treehouse Bread Company" }
grocery_item["food"] = true if grocery_item.has_value?("Bread")
Actually, your code should've failed if the test cases have done a better job checking for correction. Because part 1 asks that a key-value pair "food" => true to be set in the Hash only if grocery_item.has_value?("Bread")
is true; your code would also insert "food" => false into Hash when that condition is false.