Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

Python Python Collections (2016, retired 2019) Slices sillyCase

Posted by newpal
newpal
1,717 Points

Is there a different approach to solving this challenge?

def sillycase(string): string1 = sillycase[:len(string)//2].lower() string2 = sillycase[len(string)//2:].upper() return string1 + string2

sillycase.py 
def sillycase(string):
    string1 = sillycase[:len(string)//2].lower()
    string2 = sillycase[len(string)//2:].upper()
    return string1 + string2
newpal
newpal
1,717 Points

Sorry, I meant the following code:

def sillycase(string):
    string1 = string[:len(string)//2].lower()
    string2 = string[len(string)//2:].upper()
    return string1 + string2

[MOD: added formatting -cf]

2 Answers

Steven Parker
Steven Parker
231,248 Points
Steven Parker
Steven Parker
231,248 Points

You seem to have the "classic" solution there. You could eliminate the temporary string variables and add one to prevent calculating the size twice, but that's just minor implementation differences, not really a change in approach:

def sillycase(string):
    half = len(string) // 2
    return string[:half].lower() + string[half:].upper()
newpal
newpal
1,717 Points
newpal
newpal
1,717 Points

Thanks Steven!