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Start your free trialKyle Petran
5,017 PointsIs there a more proper way to do this?
Is there a more optimal or concise way to complete this challenge? Thanks, Kyle
# combo([1, 2, 3], 'abc')
# Output:
# [(1, 'a'), (2, 'b'), (3, 'c')]
def combo(itery1, itery2):
x=[]
for itm in range(len(itery1)):
x+=[(itery1[itm], itery2[itm])]
return x
1 Answer
Steven Parker
231,275 PointsThere's a more compact solution for the task, but the challenge specifically does not allow it as an answer:
def combo(itery1, itery2):
return list(zip(itery1, itery2))