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Start your free trialAnthony Grodowski
4,902 PointsIs there a way to return multiple items from for loop?
///SOLVED BY MYSELF\\ From the function I get only 1 item, while in my workspace code ( https://w.trhou.se/ui90o6esq7 ), which ends with print I get everything I need - full set of items. Is there a possibility to return multiple values from for loop? As far as I'm concerned for loop returns only the first item. It's important to me because later I need to join together these items to one list and then return it.
COURSES = {
"Python Basics": {"Python", "functions", "variables",
"booleans", "integers", "floats",
"arrays", "strings", "exceptions",
"conditions", "input", "loops"},
"Java Basics": {"Java", "strings", "variables",
"input", "exceptions", "integers",
"booleans", "loops"},
"PHP Basics": {"PHP", "variables", "conditions",
"integers", "floats", "strings",
"booleans", "HTML"},
"Ruby Basics": {"Ruby", "strings", "floats",
"integers", "conditions",
"functions", "input"}
}
def covers(objectt):
list_keys = [k for k in COURSES]
list_values = [v for v in COURSES.values()]
for topics in list_values:
if objectt & topics:
mutual_courses = objectt & topics
return[(list(COURSES.keys())[list(COURSES.values()).index(topics)])]
2 Answers
Anthony Grodowski
4,902 PointsAlright, I've got this
def covers(objectt):
my_list = []
list_keys = [k for k in COURSES]
list_values = [v for v in COURSES.values()]
for topics in list_values:
if objectt & topics:
mutual_courses = objectt & topics
my_list.append((list(COURSES.keys())[list(COURSES.values()).index(topics)]))
return my_list
matth89
17,826 PointsNice work! Glad you solved it. A trick that may come in handy next time; you can loop through keys and values in a dictionary with ease using .items(). Example:
for key, value in my_dict.items():
# some logic