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Python Comparison Challenge

Posted by Thomas Hilt
Thomas Hilt
956 Points

Is there is way to make this cleaner?

is there a way to make this any cleaner? or to make "if is_fizz and is_buzz" be the last option on the list? or does it have to be the first one?

Edit, how do i add a screenshot of my work?

https://w.trhou.se/6m4704limq

Chris Freeman
Chris Freeman
Treehouse Moderator 68,457 Points
Chris Freeman
Chris Freeman
Treehouse Moderator 68,457 Points

To link to an image, save the image at an external URL, say, on Imgur. Then link to image use the format ![alt text](/path/to/img.jpg "Title")

1 Answer

Chris Freeman
MOD
Chris Freeman
Treehouse Moderator 68,457 Points
Chris Freeman
Chris Freeman
Treehouse Moderator 68,457 Points

You code is as straightforward as can be expected. The if/elif/else is the only choice for now.

Coming in Python 3.10, there will be a match/case statement as defined in PEP 634.

match (number % 3 == 0, number % 5 == 0):
    case (True, False):
        print(f"{number} is Fizz")
    case (False, True):
        print(f"{number} is Buzz")
    case (True, True):
        print(f"{number} is FizzBuzz")
    case _:
        print(f"{number} is neither Fizz nor Buzz")