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Python Python Collections (2016, retired 2019) Dictionaries String Formatting with Dictionaries

Manish Giri
Manish Giri
16,266 Points
Posted by Manish Giri
Manish Giri
16,266 Points

Is this the expected solution for using ** for unpacking the dict?

For this challenge, I feel like I'm missing something. My solution was - 

def string_factory(ldict):
    return [template.format(**dct) for dct in ldict]

Even though it worked, but since List Comprehension isn't covered in the track so far, I think this challenge expects a different solution.

What is the expected solution using ** for unpacking?

string_factory.py 
# Example:
# values = [{"name": "Michelangelo", "food": "PIZZA"}, {"name": "Garfield", "food": "lasagna"}]
# string_factory(values)
# ["Hi, I'm Michelangelo and I love to eat PIZZA!", "Hi, I'm Garfield and I love to eat lasagna!"]

template = "Hi, I'm {name} and I love to eat {food}!"
Keith Whatling
Keith Whatling
17,759 Points
Keith Whatling
Keith Whatling
17,759 Points

You're "meant" to do it by looping and appending each iteration to a list and then return the list. = too many lines of code.

List comprehension IMHO should always be used unless it impacts on readability. Its just plain sexy (god I need to get out more).