Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trial
nicholas Christie
433 PointsIt has to be something simple but cant figure it out z.z
it is not recognising my .join()
available = "banana split;hot fudge;cherry;malted;black and white"
sundaes= available.split(';')
menu= "Our available flavors are: {}."
display_menu= "Our available flavors are: {}.".format(",".join(sundaes))
3 Answers
Valeshan Naidoo
27,008 PointsPretty close, if you're doing the single line implementation then
available = "banana split;hot fudge;cherry;malted;black and white"
sundaes= available.split(';')
menu= "Our available flavors are: {}.".format(", ".join(sundaes))
I think you forgot to add the space between the comma in ", " for the join().
Steven Parker
230,995 PointsThe challenge instructions say "reassign the menu variable", but you put your results into "display_menu" instead.
Also, it says the list should be "rejoined together by a comma and a space", but you're missing the space.
Stuart McIntosh
Python Web Development Techdegree Graduate 22,874 PointsHi there, just add your formatting after the menu string but with a space after the comma in your join