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Python Python Basics (2015) Letter Game App Even or Odd Loop

Gianpaul Rachiele
Gianpaul Rachiele
4,844 Points
Posted by Gianpaul Rachiele
Gianpaul Rachiele
4,844 Points

It keeps telling me there was a problem and won't submit my code. Is it because there is no break in the loop?

I can't tell if there is a problem with my code or a technical problem on the website's end. It keeps telling me there is a communication error.

import random

start = 5

def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2

while True:
  integer = random.randint(1, 99)
  if even_odd(integer) == True:
    print("{} is even".format(integer))
  else:
    print("{} is odd".format(integer))
  start -= 1

3 Answers

Josh Keenan
Josh Keenan
20,315 Points
Josh Keenan
Josh Keenan
20,315 Points

You need to change your loop! It's infinite!

while start != 0:

False can mean 0 and it does in this instance!

Afrid Mondal
Afrid Mondal
6,255 Points
Afrid Mondal
Afrid Mondal
6,255 Points

Hey Gianpaul, Actually the challenge is asking you to continue the loop until the start is false. So, you have to check your condition against start.

import random
def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2

start = 5

while start:
  integer = random.randint(1, 99)
  if even_odd(integer) == True:
    print("{} is even".format(integer))
  else:
    print("{} is odd".format(integer))
  start -= 1
Anish Walawalkar
Anish Walawalkar
8,534 Points
Anish Walawalkar
Anish Walawalkar
8,534 Points

Hey you're doing great, you just made a couple of small mistakes:

  1. your while loop never ends become while True will never be false. you should change that to while start
  2. You don't need to check even_odd(integer) == True, you can just check even_odd(integer)

in code:

import random

start = 5

def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
  return not num % 2

while start:
  integer = random.randint(1, 99)
  if even_odd(integer):
    print("{} is even".format(integer))
  else:
    print("{} is odd".format(integer))
  start = start - 1