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Python Python Collections (2016, retired 2019) Dictionaries Word Count

TECH TEAM
TECH TEAM
5,363 Points
Posted by TECH TEAM
TECH TEAM
5,363 Points

It works in my pc but "Bummer!" here. Could you please tell me what I am doing wrong?

Here my code attached, thanks is advance!

wordcount.py 
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.

def word_count(one_string):
    result={}
    lower_string = one_string.lower()
    list_string = lower_string.split(' ')
    for eachword in list_string:
        if eachword not in result:
            result[eachword]=1
        elif eachword in result:
            result[eachword]=result[eachword]+1
    return result

1 Answer

Jennifer Nordell
seal-mask
STAFF
.a{fill-rule:evenodd;}techdegree
Jennifer Nordell
Treehouse Teacher
Jennifer Nordell
.a{fill-rule:evenodd;}techdegree
Jennifer Nordell
Treehouse Teacher

Hi there! Yes, it partially works on your PC, but that's because your test data is not comprehensive. When I run your code in the challenge it gives this clue in the Bummer! message:

Hmm, didn't get the expected output. Be sure you're lowercasing the string and splitting on all whitespace!

While you are lowercasing the string, you aren't splitting on all whitespace. My guess is that your test data didn't include any strings with tabs or newline characters. Those are also whitespace.

This tells Python to split on spaces:

split(' ')

But this tells Python to split on all whitespace:

split()

Hope this helps! :sparkles: