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Start your free trialJames Morris
5,104 PointsI've labbed the code and I'm getting the result it requests. what am I doing wrong?
I've tried this on my pc and the result comes back as expected. is there an extra requirement I've overlooked?
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(string):
#convert string into a list broken up by spaces " "
string = string.lower()
result = string.split(" ")
#make empty dictionary
my_dict = {}
#make key for counting
key = 0
#make check_list
check_list = []
#for each word in list see how many times it occurs and add 1 to key
for word in result:
#check check_list for word
if word in check_list:
continue
else:
key = result.count(word)
my_dict.update({word: key})
check_list.append(word)
return my_dict
2 Answers
Wesley Trayer
13,812 PointsJust pasted your code into the challenge and it only needs one change,
result = string.split(" ")
should be:
result = string.split()
I think this is so if there is more than one space between words it removes all white space.
James Morris
5,104 PointsExcellent! thanks that worked.
That makes sense for double spacing, cheers