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Stormy Silver
9,240 PointsI've never had such a hard time with a challenge.
The message in the final echo command only makes sense if your favorite flavor is the same as mine. Add a conditional around that final echo command that checks if the flavor variable has a value of "cookie dough." (Remember to choose carefully between using a single equal sign and a double equal sign in the check.) Preview the code and, if you have a different flavor, make sure the message disappears.
This is what I have so far:
<?php $flavor = "mint";
echo "<p>Your favorite flavor of ice cream is "; echo $flavor; echo ".</p>"; echo "<p>Randy's favorite flavor is cookie dough, also!</p>";
?>
1 Answer
Andrew McCormick
17,730 PointsStormy, See the video right before the challenge at the 2:20 mark video here
It would be something like this:
<?php
$foo = "bar";
echo "this is some text";
if ($foo == "bar") {
echo "hey hey hey... foo does equal bar";
}
?>
remember that single equal sign will assign a variable a value, double equal will compare the value of the variable to the the information you want to compare it to.
Stormy Silver
9,240 PointsStormy Silver
9,240 PointsOkay thank you I'll check that out.
Joe Hirst
Courses Plus Student 6,489 PointsJoe Hirst
Courses Plus Student 6,489 PointsThis example makes calling variables much easier to understand. Thanks Andrew!