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aycee morrow
1,767 PointsjQuery's $.get() method doesn't do anything if the server returns an error. You can chain jQuery's fail() method to the
jQuery's $.get() method doesn't do anything if the server returns an error. You can chain jQuery's fail() method to the $.get() method and pass it a function to handle any errors. Start by adding the fail() method to the $.get() method.
$.get("missing.html", function(data) {
$("#footer").html(data);
.fail();
});
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<title>AJAX with JavaScript</title>
</head>
<body>
<div id="main">
<h1>AJAX with jQuery</h1>
</div>
<div id="footer"></div>
<script src="jquery.js"></script>
<script src="app.js"></script>
</body>
</html>
1 Answer
Osaro Igbinovia
Full Stack JavaScript Techdegree Student 15,928 PointsHi Aycee, you're to CHAIN the 'fail' method to the $.get method. You added the 'fail' method(to no object) INSIDE the $.get method:
$.get("missing.html", function(data) {
$("#footer").html(data);
.fail();
});
The challenge wants you to add/chain the 'fail' method to the $.get method. Think of the $.get() as an object you're chaining the fail() to :
$.get().fail();
Adding in the callback with the 'jqXHR' parameter and the alert statement, the end result should look like this:
$.get("missing.html", function(data) {
$("#footer").html(data);
}).fail(function (jqXHR) {
alert(jqXHR.statusText);
});