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Start your free trialDerek Vha
10,452 PointsJS - Code is not printing out 1 student details - Unsure
Hi All,
I've been trying to solve this problem from this JavaScript video.
I've created a function called searchStudents that loops through the array of students. This function has two parameters, the studentname to search on, and emptystring which will return the matches student details.
However once I call my function, the emptstring should be populated (if it finds a matching student name), and then this should be printed via the Print function. However nothing happens. Any ideas? Theres no syntax errors in my code.
var message = '';
var student;
var input = '';
var emptystring = '';
function print(message) {
var outputDiv = document.getElementById('output');
outputDiv.innerHTML = message;
}
function searchStudents(studentname,emptystring)
{
for (var i = 0; i < students.length; i += 1) {
student = students[i];
message += '<h2>Student: ' + student.name + '</h2>';
message += '<p>Track: ' + student.track + '</p>';
message += '<p>Points: ' + student.points + '</p>';
message += '<p>Achievements: ' + student.achievements + '</p>';
if (studentname === student.name)
{
emptystring = message;
//console.log("we got into function! " + emptystring);
return emptystring;
// break;
}
}
}
while (input != "quit")
{
emptystring = '';
input = prompt("Search student records : type a name [Jody], (or type 'quit' to end)");
if (input == "quit")
{
break;
}
else
{
searchStudents(input,emptystring)
//console.log("this should print " + emptystring);
print(emptystring);
}
}
(Note - the array called Students is in its own JS file)
Many thanks
1 Answer
Manish Giri
16,266 PointsI think, the problem lies here -
else
{
searchStudents(input,emptystring)
//console.log("this should print " + emptystring);
print(emptystring);
}
- This function returns a string which is the populated message. But you're not saving the return value anywhere -
searchStudents(input,emptystring)
. So your function result is basically lost. - When you get to the next line
print(emptystring);
, the value ofemptyString
is still""
, as it was initialized here - emptystring = '';`.
So it prints nothing.
Derek Vha
10,452 PointsDerek Vha
10,452 PointsThankyou. Im too used to C# way of things!