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Start your free trialY. Kravets
10,350 PointsKeep getting: 'Some of the words seem to be missing!'
Hi guys!
Admittedly still trying to get myself comfortable with dictionaries and its not going really well. I could use your opinion on what is it I am doing wrong with this code. Thanks!
def word_count(my_st):
my_dict = {}
my_st.lower()
my_st.split()
for item in my_st:
if item in my_dict:
my_dict[item] += 1
else:
my_dict[item] = 1
return my_dict
# E.g. word_count("I am that I am") gets back a dictionary like:
# {'i': 2, 'am': 2, 'that': 1}
# Lowercase the string to make it easier.
# Using .split() on the sentence will give you a list of words.
# In a for loop of that list, you'll have a word that you can
# check for inclusion in the dict (with "if word in dict"-style syntax).
# Or add it to the dict with something like word_dict[word] = 1.
4 Answers
Andre' Jones
26,671 Pointsthe split method works excatly as you explained, but you didnt assign it back to the variable so once you get to the for loop my_string is still = "I love treehouse".
This is what you should do;
my_str = my_str.split()
Andre' Jones
26,671 PointsYour problem is the split.
I'll give you a hint but not the Answer so you can think through it.
this is the result your getting now {'a': 3, ' ': 4, 'I': 2, 'h': 1, 'm': 2, 't': 2}
Hint: A string is an array of characters
Y. Kravets
10,350 PointsHi Andre! Thanks for your answer, as a clarification though: to my understanding of the task I need to separate words out of the given string first. I thought that if for example:
my_string = "I love treehouse" my_string.split() would give me then: ["I", "love", "treehouse"], which is exactly what I need because then I go item by item (so in this case word by word).
Am I wrong somewhere?
Y. Kravets
10,350 PointsFor some unexplainable reason I led myself to believe that once I do my_str.split() it automatically updates my_str to be the output of that. Well, didn't think it through carefully enough. Thank you for pointing it out Andre!