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Start your free trialLok C
10,617 PointsKept getting the error 'Where's most_classes()?'
Hi, it seems that no matter what I do - i kept getting the error 'Where's 'most_classes()'? Whether it works or not, it's obviously there, not sure how to fix it.
# The dictionary will be something like:
# {'Jason Seifer': ['Ruby Foundations', 'Ruby on Rails Forms', 'Technology Foundations'],
# 'Kenneth Love': ['Python Basics', 'Python Collections']}
#
# Often, it's a good idea to hold onto a max_count variable.
# Update it when you find a teacher with more classes than
# the current count. Better hold onto the teacher name somewhere
# too!
#
# Your code goes below here.
def most_classes(somedic):
names = []
for key in somedic:
names.append(key)
num = {}
for name in names:
count = 0
for value in thedic[name]:
count += 1
num[name] = count
max_count = 0
for key in num.keys():
if num[key] > max_count:
most = key
max_count = num[key]
else:
pass
return most
1 Answer
Amanda Harman
11,303 PointsI am not sure why it is throwing down that error in particular, but your code is a lot longer than it has to be. For one, you should not have to create a list to create this function. Dictionaries are really powerful in Python because of their convenient methods for retrieving data. Remember:
for akey in somedic.keys():
print(akey)
would return each key in the dictionary. In addition:
for akey in somedic.keys():
print(somedic[akey]))
would return the values associated with each particular key.
So try to approach the problems using the tools available for dictionaries .
Hope this helps!
Amanda Harman
11,303 PointsAmanda Harman
11,303 PointsAlso the len() function helps a lot for this problem!
Lok C
10,617 PointsLok C
10,617 PointsThank you! I was able to make the code shorter with your suggestion.