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Python Python Collections (Retired) Lists Redux Manipulating Lists

Logan Wu
Logan Wu
10,792 Points
Posted by Logan Wu
Logan Wu
10,792 Points

Learn Python Challenge Task 2 of 3

I tried switching different ways by trying both .remove and del to remove the three items, but it still doesn't work. Can anyone help? Thanks!

lists.py 
the_list = ["a", 2, 3, 1, False, [1, 2, 3]]

# Your code goes below here
new_list = the_list.insert(0, the_list.pop(3))

new_list.remove("a")
del new_list[4]
new_list.remove([1, 2, 3])
Shadow Skillz
Shadow Skillz
3,020 Points
Shadow Skillz
Shadow Skillz
3,020 Points

I'm having the same issue

item = the_list.pop(3)
the_list.insert(0,item)
the_list.remove(False)
the_list.remove([1,2,3])
del the_list[0]

3 Answers

Dan Johnson
Dan Johnson
40,533 Points
Dan Johnson
Dan Johnson
40,533 Points

Since you've removed "a" before using del, False will no longer be at index 4:

the_list.insert(0, the_list.pop(3)) #[1, 'a', 2, 3, False, [1, 2, 3]]
the_list.remove("a") #[1, 2, 3, False, [1, 2, 3]] False is now at index 3
del the_list[3]
the_list.remove([1, 2, 3])
Logan Wu
Logan Wu
10,792 Points
Logan Wu
Logan Wu
10,792 Points

Now I get it. Thank you.

Unsubscribed User
Unsubscribed User
6,312 Points
Unsubscribed User
Unsubscribed User
6,312 Points

as easy as this

list_1 = [1, 2, 3] list_2 = [4, 5, 6] list_3 = (list_1 + list_2)