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Start your free trialMUZ140847 Ralph Dendere
3,690 Pointslist output
,
dicts = [
{'name': 'Michelangelo',
'food': 'PIZZA'},
{'name': 'Garfield',
'food': 'lasanga'},
{'name': 'Walter',
'food': 'pancakes'},
{'name': 'Galactus',
'food': 'worlds'}
]
string = "Hi, I'm {name} and I love to eat {food}!"
def string_factory(list1,string1):
newItem = list()
for dictionary in list1:
newVariable = dictionary
new_sentence = string1.format(**newVariable)
newItem.append(new_sentence)
return newItem
2 Answers
Adam Raitano
5,387 PointsOh, and you might want to dedent that return statement.
Adam Raitano
5,387 PointsA few things,
you don't need to give 'dictionary' a 'newVariable'. You can just use 'dictionary'. Also, just make newItem an open list like
newItem = [] ( I also think list(newItem) would work but don't quote me on that)
You can also just straight append the newItem (which is the list you will be returning). No need to create a new variable for that either. And because newVariable is not a thing anymore, don't forget to remove all instances of it in your code and replace it with the proper variable name... ;-)