Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

PHP Build a Simple PHP Application Listing Inventory Items More Excitement With Arrays

Listing Inventory Items, Stage 4, task 6/7

I'm trying to understand this question. Any thoughts?

"Inside the foreach loop, we should only display one <li> tag for each flavor. The one list item should display the value for the array element that the foreach loop is considering. Remove one of the <li> elements, and change the value that gets displayed in the other to display the flavor."

<?php

$flavors = array("Chocolate", "Vanilla", "Mint");

?> <p>Welcome to Ye Olde Ice Cream Shoppe. We sell <?php echo count($flavors); ?> flavors of ice cream.</p> <ul> <?php foreach($flavors as $flavor) { ?> <li><?php echo $flavors[0]; ?></li> <li><?php echo $flavors[1]; ?></li> <li><?php echo $flavors[2]; ?></li> <?php } ?> </ul>

2 Answers

Adam Moore
Adam Moore
21,956 Points

With the for each loop, you don't have to list each item in the array. So, you just use the variable you set inside the foreach loop ($flavor) for each one of the items in the astray $flavors. So, simply echoing "$flavor" once will echo all of the flavors in $flavors as it runs for each of the items in the array.

Thanks man. Appreciate the info.