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Saloni Gandhi
1,531 Pointslists.py
please help me out
the_list = ["a", 2, 3, 1, False, [1, 2, 3]]
new=the_list.pop(3)
the_list.insert(0,new)
# Your code goes below here
del the_list[1]
del the_list[4]
del the_list[5]
Chris Freeman
Treehouse Moderator 68,441 PointsGood job, Michel, for solving it in a single line.
This is one case where the challenge grader is lenient. The specific text says "You can do this in one step..." [emphasis mine] but it is not required.
Michel van Essen
8,077 PointsGot you, that makes sense! Thanks for your presence by the way, you are on a lot of topics that helped me out huge!
1 Answer
Chris Freeman
Treehouse Moderator 68,441 PointsOne hazard when removing items from a list is the indexes change after each deletion. While your three del statements would work if the index were constant, they need to be adjusted to account for the changing indexes:
the_list = ["a", 2, 3, 1, False, [1, 2, 3]]
new=the_list.pop(3)
the_list.insert(0,new)
# Your code goes below here
del the_list[1] # <-- This is OK
del the_list[3] # <-- False shifted to index 3 when 'a' is removed
del the_list[3] # <-- List shifted to index 3 when False is removed
One way to avoid the changing indexes is to remove from the back towards the front:
del the_list[5]
del the_list[4]
del the_list[1]
Michel van Essen
8,077 PointsMichel van Essen
8,077 PointsI just noticed that you're first task is not what the challenge asked for. The first task asked to pop and insert with one line of code, so I would replace your first line of code with: the_list.insert(0, the_list.pop(3))