Make a new variable, var_two, with "e" at index -2. Remember, negative indexes start at the right side of the iterable.

The challenge is asking you to create a new variable called "var_two". This variable is going to be equal to a list, string, dictionary, tuple ext... anything with an 'e' at the index of -2. Think of it like this...

'''      0     1     2     3     4     5
      _____________________________________
      |  a  |  p  |  p  |  l  |  e  |  s  |
      -------------------------------------
        -6    -5    -4    -3    -2    -1
'''

As long as you have an 'e' in that spot you would be completing the challenge by using var_two = 'apples' because 'e' is at an index of -2.

var_one = ['a','b','c','d','e', 't']

var_two[-2] = ['a','p','p','l','e']

not working

"Ramon Villarreal-Leal 15 minutes ago var_one = ['a','b','c','d','e', 't']

var_two[-2] = ['a','p','p','l','e']

not working"

Ramon, the way you have the variable declared, the 'e' is in index -1. Remember, when going backwards through an iterable it starts at -1 then -2, -3, and so on. if you were to add one more string at the end of your list like 's' to make it

['a', 'p', 'p', 'l', 'e', 's']

it will pass because then the 'e' is at -2 because the 's' will be at -1.