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Start your free trialThomas Katalenas
11,033 PointsMembers
def members(my_dict, my_list): count = 0 for i in my_list: if i in my_dict: count += 1 return count
whats wrong with my code?
2 Answers
Evan Demaris
64,262 PointsNothing's wrong with your code - except perhaps your formatting? It passes the Challenge when I format as below (whitespace is the only thing changed).
def members(my_dict, my_list):
count = 0
for i in my_list:
if i in my_dict:
count += 1
return count
alex novickis
34,894 Pointsassuming you have correct indents,
when you do "if i in my_dict" you are looking through the keys in the dict if you mean to look through the values I would try "if i in my_dict.values()"
consider this example
my_d = { "name": "alex", "permissions": "root", "password": "xyzzy" }
"alex" in my_d
False
"name" in my_d
True
And looking through values
"alex" in my_d.values()
True
Evan Demaris
64,262 PointsThe Challenge that Thomas wrote his code for is asking for the list items which match the dictionary keys, so his code is correct - unless you were just letting him know how to run through the values if he wanted to do that in another project.